A pitot tube is inserted in a pipe of $300\text{mm}$ dia. The static…

Question

A pitot tube is inserted in a pipe of $300\text{mm}$ dia. The static pressure in a pipe is $100\text{mm}$ of mercury (vacuum). The stagnation pressure at the center of the pipe, recorded by the pitot tube is $0.981\text{ N/cm}^2$. Calculate the rate of flow of water through pipe, if the mean velocity of flow is $0.85$ times the central velocity. Take $C_v = 0.98$.

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