Draw the graph of the series: $f(x) = \begin{cases} -x, & -2 \le x <…

Question

Draw the graph of the series:

$f(x) = \begin{cases} -x, & -2 \le x < -1 \\ 2 - x^2, & -1 \le x \le 1 \\ x, & 1 < x \le 2 \end{cases}$

Is it even or odd? Also expand $f(x)$ as a Fourier series in $(-2, 2)$.

Related pages

• Odd and Even Functions — topic
• Engineering Mathematics-II syllabus

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